Sunday, October 13, 2013

Math Paper

Chapter 6 paradox 6: Suppose that the population banal divagation (?) for a normally distri moreovered standardized stress of motion is know to be 7.20. What would the standard error of the sample soaked ([pic]) be if we were to draw a random sample of 16 test scores? firmness: For this problem, since the population standard spillage is given, we utilise the rule on varlet 193. [pic] =[pic] Therefore: [pic] = [pic] =[pic] = 1.8 chore 7: Suppose that the random sample from difficulty 6 yielded these ascertained scores: 656125101113 121092023202818 a. Find the 95% boldness time separation for the cerebrate. b. Find the 99% arrogance interval for the mean. Answer: The offshoot thing we need to do is stop the mean for these entropy (we will employ the population standard deviation but if we did not know it we would have to calculate that and use the t distribution). Using Excel the mean is 13 (you should insist this appr eciate for practice). a. this instant the 95% confidence interval is raise use the formula on page 196: 95% confidence interval = [pic] ± 1.96 [pic] so we then have: 13 ±1.96 (1.8) = 13 ± 3.528 = 9.47 to 16.53 b. Now the 99% confidence interval is embed using the formula on page 197: 99% confidence interval = [pic] ± 2.58 [pic] so we then have: 13 ±2.58 (1.8) = 13 ± 4.644 = 8.36 to 17.
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64 puzzle 8 Now suppose that we do not tactile sensation wanton assuming that ? = 7.20. Use the scores in Problem 7 to: a. estimate the standard error of the sample mean ([pic]). b. mystify the 95% confidence interval for the mean. c. keep an eye on the 99% confidence interval for the mean. Answer: First ! we need to find the standard deviation from our sample. I used Excel and found it to be (S = 6.899) but please verify! Now we would get the precedent Error of the mean using the formula on page 202: [pic] =[pic] a. Therefore: [pic] = [pic] =[pic] = 1.78 The general formula for the confidence interval is shown on page 205: Confidence...If you want to get a intact essay, direct it on our website: OrderEssay.net

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